szw52ts91l的部落格

標題:

A F. 2 Maths question - Factorization by using identities

發問:

A F. 2 Maths question - Factorization by using identities a^2-8a+16-y^2 Please show your working steps clearly and explain your answer in details.

最佳解答:

a^2 - 8a + 16 - y^2 = a^2 - 2(a)(4) + 4^2 - y^2 = (a - 4)^2 - y^2∵(a - b)^2 = a^2 - 2ab + b^2 = (a - 4 + y)(a - 4 - y)∵a^2 - b^2 = (a + b)(a - b)

其他解答:

• F&C 既地址
• maths Q ... 超急... tmr 要交啦 ....@1@
• 上班買袋Prefer Agnes b , Gucci or Other--

此文章來自奇摩知識+如有不便請留言告知

a^2-8a+16-y^2 =(a-4)^2-y^2 =[(a-4)+y][(a-4)-y] =(a-4+y)(a-4-y)|||||a^2 - 8a + 16 - y^2 = a^2 - 2(a)(4) + 4^2 - y^2 = (a - 4)^2 - y^2∵(a - b)^2 = a^2 - 2ab + b^2 = (a - 4 + y)(a - 4 - y)∵a^2 - b^2 = (a + b)(a - b)