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標題:

[40分]中二級數學問題

發問:

1.(a) (2x2-3x+5)+(x2-7x-9) 1.(b) (4x2-2-x3+3x)+(5x-9+x3-6x2) 2.(a)(1-c-c2)-(2c-3c2) 2.(b)(2x2-5x四次方-12)-(9+4x四次方-x3+2x2) 3.(a)(-6m四次方-8+3m-m3)+(4m四次方+m2+7m3-2) 3.(b)(-10-5x3+2x+3x2)-(4x-6x2-x四次方-4) 4.(a)(2a+b)-(a-b)+(3a-4b) 4.(b)(x2+2x)+(x2-1)-(3x-3) 真的想透腦筋` 怎麼想也想不了` 請幫幫我,這是40分的問題`

最佳解答:

• The probability-
• 1.設f(x)為二次函數,若f(-1)=1,f(1)=3,f(2)=7,則f(5)=-2.設degf(x)=3,f(97)=11,f(98)=9,f(99)=25,f(100)=41,則f(96)=- (限使用拉格郎日法)-@1@
• 40分：便利店﹑報攤等通常每天早上幾點就會有報紙售賣﹖

• The probability-
• 1.設f(x)為二次函數,若f(-1)=1,f(1)=3,f(2)=7,則f(5)=-2.設degf(x)=3,f(97)=11,f(98)=9,f(99)=25,f(100)=41,則f(96)=- (限使用拉格郎日法)-@1@
• 40分：便利店﹑報攤等通常每天早上幾點就會有報紙售賣﹖

 

此文章來自奇摩知識+如有不便請留言告知

1.(a) (2x-3x 5) (x-7x-9) =3x-10x-4 1.(b) (4x-2-x 3x) (5x-9 x-6x) =-2x 8x-11 2.(a)(1-c-c)-(2c-3c) =2c-3c 1 2.(b)(2x-5x^4-12)-(9 4x^4-x 2x) =-9x^4 x-21 3.(a)(-6m^4-8 3m-m) (4m^4 m 7m-2) =-2m^4 6m m 3m-10 3.(b)(-10-5x+2x+3x)-(4x-6x-x^4-4) =x^4-5x +9x-2x-6 4.(a)(2a+b)-(a-b)+(3a-4b) =(a+2b)+(3a-4b) =4a-2b 4.(b)(x+2x)+(x-1)-(3x-3) =(2x+2x-1)-(3x-3) =2x-x+2 希望幫到你啦!!

其他解答:

1a.=(2+1)x^2+(-3-7)x+(5-9) =3x^2-10x-4 1b.=(-1+1)c^3+(4-6)c^2+(3+5)c+(-2-9) =-2x^2+8x-11 =2x^2-8x+11 2a.=(-1-(-3)c^2-(-1-2)c+1 =2c^2+3c+1 2b.=(-5-4)x^4+(0-(-1))x^3+(2-2)x^2+(0-0)x+(-12-9)+ =-9x^4+x^3-21 3a. (-6+4)m^4+(-1+7)m^3+(0+1)m^2+(3+0)m+(-8-2) =-2m^4+6m^3+m^2+3m-10 =2m^4-6m^3-m^2-3m+10 3b. (0-(-1))x^4+(-5-0)x^3+(3-(-6))x^2+(2-4)x+(-10-(-4)) =x^4-5x^3+9x^2-2x-6 4a. (2-1+3)a+(1-1-4)b =4a-4b =a-b 4b (1+1)x^2+(2-3)x+(-1-(-3)) =2x^2-x+2|||||40分]中二級數學問題 7x6=42+86x12=88 42+56-162+802=710 445+632-5632=9562 452163+1+2+3+-------+50=400